What is the integral of 3/(sqrt(y)) ?

The integral of 3/(sqrt(y)) is 6sqrt(y)+C

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integral of 3/(sqrt(y))

\int \frac{3}{y} d y

6 y + C

Solution steps

\int \frac{3}{y} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int \frac{1}{y} d y

Apply the Power Rule

: 2 y^{\frac{1}{2}}

= 3 \cdot 2 y^{\frac{1}{2}}

Simplify

3 \cdot 2 y^{\frac{1}{2}} : 6 y

= 6 y

Add a constant to the solution

= 6 y + C

x \to 1 lim (\frac{- 3 x - 1}{x - 1})

\int (e^{x} + 2)^{2} e^{x} d x

2 sin (3 θ), 1

\frac{d}{d x} (4 e^{2 x} x + 4 e^{2 x})

\int (2 x + 3 x^{2}) d x