What is the derivative of 4e^{2x}x+4e^{2x} ?

The derivative of 4e^{2x}x+4e^{2x} is 8e^{2x}x+12e^{2x}

What is the first derivative of 4e^{2x}x+4e^{2x} ?

The first derivative of 4e^{2x}x+4e^{2x} is 8e^{2x}x+12e^{2x}

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\frac{d}{d x} (4 e^{2 x} x + 4 e^{2 x})

8 e^{2 x} x + 12 e^{2 x}

Solution steps

\frac{d}{d x} (4 e^{2 x} x + 4 e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 e^{2 x} x) + \frac{d}{d x} (4 e^{2 x})

\frac{d}{d x} (4 e^{2 x} x) = 4 (2 e^{2 x} x + e^{2 x})

\frac{d}{d x} (4 e^{2 x}) = 8 e^{2 x}

= 4 (2 e^{2 x} x + e^{2 x}) + 8 e^{2 x}

Simplify

4 (2 e^{2 x} x + e^{2 x}) + 8 e^{2 x} : 8 e^{2 x} x + 12 e^{2 x}

= 8 e^{2 x} x + 12 e^{2 x}

\int (2 x + 3 x^{2}) d x

y = x^{3} - 3 x + 1, (2, 3)

\int (in t)^{2} d t

y = - 18

\frac{d}{d x} (2 sec^{2} (x^{7}))

What is the derivative of 4e^{2x}x+4e^{2x} ?
The derivative of 4e^{2x}x+4e^{2x} is 8e^{2x}x+12e^{2x}
What is the first derivative of 4e^{2x}x+4e^{2x} ?
The first derivative of 4e^{2x}x+4e^{2x} is 8e^{2x}x+12e^{2x}