What is (\partial)/(\partial y)(-2xy(-15-x-y)) ?

The answer to (\partial)/(\partial y)(-2xy(-15-x-y)) is -2x(-15-x-2y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(-2xy(-15-x-y))

\frac{\partial}{\partial y} (- 2 x y (- 15 - x - y))

- 2 x (- 15 - x - 2 y)

Solution steps

\frac{\partial}{\partial y} (- 2 x y (- 15 - x - y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 x \frac{\partial}{\partial y} (y (- 15 - x - y))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = - 15 - x - y

= - 2 x (\frac{\partial}{\partial y} (y) (- 15 - x - y) + \frac{\partial}{\partial y} (- 15 - x - y) y)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (- 15 - x - y) = - 1

= - 2 x (1 \cdot (- 15 - x - y) + (- 1) y)

Simplify

- 2 x (1 \cdot (- 15 - x - y) + (- 1) y) : - 2 x (- 15 - x - 2 y)

= - 2 x (- 15 - x - 2 y)

\int_{0}^{1} \frac{2}{x ( x + 1 )} d x

y = 4.2 x - x^{2}

\int \frac{700 x}{( x + 1 ) ^{\frac{1}{3}}} d x

\frac{\partial}{\partial x} (x e^{- x^{2} - y^{2}})

x \to 0 lim (\frac{e ^{x} - 1}{9 x})

What is (\partial)/(\partial y)(-2xy(-15-x-y)) ?
The answer to (\partial)/(\partial y)(-2xy(-15-x-y)) is -2x(-15-x-2y)