What is the derivative of (x-1(x+2)) ?

The derivative of (x-1(x+2)) is 2x+1

What is the first derivative of (x-1(x+2)) ?

The first derivative of (x-1(x+2)) is 2x+1

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\frac{d}{d x} ((x - 1) (x + 2))

2 x + 1

Solution steps

\frac{d}{d x} ((x - 1) (x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 1, g = x + 2

= \frac{d}{d x} (x - 1) (x + 2) + \frac{d}{d x} (x + 2) (x - 1)

\frac{d}{d x} (x - 1) = 1

\frac{d}{d x} (x + 2) = 1

= 1 \cdot (x + 2) + 1 \cdot (x - 1)

Simplify

1 \cdot (x + 2) + 1 \cdot (x - 1) : 2 x + 1

= 2 x + 1

\frac{1}{7} π r^{3}

\frac{\partial}{\partial x} (ln (3 x))

x \to \infty lim (8 x^{2} e^{- x})

y^{^{''}} - y^{^{'}} + y = e^{2 t}

\frac{d}{d x} (x (cosh (\frac{200}{x}) - 1) - 100)

What is the derivative of (x-1(x+2)) ?
The derivative of (x-1(x+2)) is 2x+1
What is the first derivative of (x-1(x+2)) ?
The first derivative of (x-1(x+2)) is 2x+1