integral from 1 to 6 of |x-3|

解答

\int_{1}^{6} ∣ x - 3 ∣ d x

\frac{13}{2}

十进制

6.5

求解步骤

\int_{1}^{6} ∣ x - 3 ∣ d x

拿掉绝对值

= \int_{1}^{3} - x + 3 d x + \int_{3}^{6} x - 3 d x

\int_{1}^{3} - x + 3 d x = 2

\int_{3}^{6} x - 3 d x = \frac{9}{2}

= 2 + \frac{9}{2}

化简

2 + \frac{9}{2} : \frac{13}{2}

= \frac{13}{2}

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