integral from 0 to 6 of h(x)

Lösung

\int_{0}^{6} h (x) d x

h \cdot 18

Schritte zur Lösung

\int_{0}^{6} h x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= h \cdot \int_{0}^{6} x d x

Wende die Potenzregel an

= h [\frac{x ^{2}}{2}]_{0}^{6}

Berechne die Grenzen:

18

= h \cdot 18

\int_{1}^{4} x e^{- x} - e^{- x} d x

\int_{- 2}^{6} h (x) d x

\int_{0}^{8} 2 d x

\int_{- 1}^{1} x^{3} (5 + x^{4})^{3} d x

\int_{- 1}^{1} \frac{1}{6} (x + 3) d x