integral of integral of cos(3x+2y)

Lösung

\int \int cos (3 x + 2 y) d y d x

C x - \frac{1}{6} cos (2 y + 3 x) + C

Schritte zur Lösung

\int \int cos (3 x + 2 y) d y d x

\int cos (3 x + 2 y) d y = \frac{1}{2} sin (2 y + 3 x) + C

= \int (\frac{1}{2} sin (2 y + 3 x) + C) d x

\int (\frac{1}{2} sin (2 y + 3 x) + C) d x = C x - \frac{1}{6} cos (2 y + 3 x) + C

= C x - \frac{1}{6} cos (2 y + 3 x) + C

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