derivative f(t)=e^{7tsin(2t)}

Lösung

ableitung von

f (t) = e^{7 t s i n (2 t)}

e^{7 t s i n (2 t)} \cdot 7 (sin (2 t) + 2 t cos (2 t))

Schritte zur Lösung

\frac{d}{d t} (e^{7 t s i n (2 t)})

Wende die Kettenregel an:

e^{7 t s i n (2 t)} \frac{d}{d t} (7 t sin (2 t))

= e^{7 t s i n (2 t)} \frac{d}{d t} (7 t sin (2 t))

\frac{d}{d t} (7 t sin (2 t)) = 7 (sin (2 t) + 2 t cos (2 t))

= e^{7 t s i n (2 t)} \cdot 7 (sin (2 t) + 2 t cos (2 t))

t an g e n t f (x) = x (27 x^{- 2} + 2), at x = - 3

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