What is the limit as x approaches 0 of 2x(ln(x))^2 ?

The limit as x approaches 0 of 2x(ln(x))^2 is Does not exist

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limit as x approaches 0 of 2x(ln(x))^2

x \to 0 lim (2 x (ln (x))^{2})

Does not exist

Solution steps

x \to 0 lim (2 x (ln (x))^{2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (2 x (ln (x))^{2}) = 0

x \to 0 - lim (2 x (ln (x))^{2}) =

Does not exist

= Does not exist

x \to 0 + lim (ln (x) ln (x + 1))

x \to - 1 lim (- - x + 1)

x \to \frac{1}{2} lim (4 x (x - \frac{1}{4}))

x \to 5 lim (\frac{4 x - 10}{4 x - 20})

m \to 0 lim (\frac{5}{m ^{2} + m} - \frac{5}{m})

What is the limit as x approaches 0 of 2x(ln(x))^2 ?
The limit as x approaches 0 of 2x(ln(x))^2 is Does not exist