y^'=y(2-ty)

Lösung

y^{^{'}} = y (2 - t y)

y = \frac{4 e ^{2 t}}{2 e ^{2 t} t - e ^{2 t} + c _{1}}

Schritte zur Lösung

y^{'} (t) = y (2 - t y)

Solve Bernoulli ODE:

y = \frac{4 e ^{2 t}}{2 e ^{2 t} t - e ^{2 t} + c _{1}}

y = \frac{4 e ^{2 t}}{2 e ^{2 t} t - e ^{2 t} + c _{1}}

d er i v a t i v e y = \frac{3 ( x - 1 )}{4 x x}

\int x sin (\frac{nπ x}{10}) d x

\frac{\partial}{\partial x} (2 x cos (x^{2} + y^{2}))

\frac{d y}{d t} = yr (1000 - y)

a re a y = sec^{2} (x), y = 8 cos (x), - \frac{π}{3}, \frac{π}{3}