What is the limit as x approaches 1 of (x^2-3)/(x-9) ?

The limit as x approaches 1 of (x^2-3)/(x-9) is 1/4

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limit as x approaches 1 of (x^2-3)/(x-9)

x \to 1 lim (\frac{x ^{2} - 3}{x - 9})

\frac{1}{4}

Decimal

0.25

Solution steps

x \to 1 lim (\frac{x ^{2} - 3}{x - 9})

Plug in the value

x = 1

= \frac{1 ^{2} - 3}{1 - 9}

Simplify

\frac{1 ^{2} - 3}{1 - 9} : \frac{1}{4}

= \frac{1}{4}

x \to - 1 + lim (1)

x \to 2 lim (4 x^{3} - 3 x - 5)

x \to 0 lim ((x + 2) \cdot e^{\frac{1}{x}})

x \to 0 lim (cos (x) sec (x))

x \to 4 + lim (3 x^{2} - 9)

What is the limit as x approaches 1 of (x^2-3)/(x-9) ?
The limit as x approaches 1 of (x^2-3)/(x-9) is 1/4