limit as t approaches 0+of tln(t^2)

Lösung

t \to 0 + lim (t ln (t^{2}))

0

Schritte zur Lösung

t \to 0 + lim (t ln (t^{2}))

Umformung für L'Hopital

= t \to 0 + lim (\frac{ln ( t ^{2} )}{\frac{1}{t}})

Wende das L'Hopital Theorem an

= t \to 0 + lim (\frac{\frac{2}{t}}{- \frac{1}{t ^{2}}})

Vereinfache

\frac{\frac{2}{t}}{- \frac{1}{t ^{2}}} : - 2 t

= t \to 0 + lim (- 2 t)

Setze den Wert

t = 0

ein

= - 2 \cdot 0

Vereinfache

= 0

x \to 0 lim (5 x ln (x))

x \to 0 lim (\frac{1}{( x - 1 ) ^{4} + 2})

x \to - \infty lim (x + e^{x})

x \to - 1 lim (x^{2} + 2 x + 4)

x \to - 2 lim (2 e^{x + 2} - 3)