What is the limit as x approaches 4 of (5x-20)/(x^2-7x+12) ?

The limit as x approaches 4 of (5x-20)/(x^2-7x+12) is 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 4 of (5x-20)/(x^2-7x+12)

x \to 4 lim (\frac{5 x - 20}{x ^{2} - 7 x + 12})

5

Solution steps

x \to 4 lim (\frac{5 x - 20}{x ^{2} - 7 x + 12})

Simplify

\frac{5 x - 20}{x ^{2} - 7 x + 12} : \frac{5}{x - 3}

= x \to 4 lim (\frac{5}{x - 3})

Plug in the value

x = 4

= \frac{5}{4 - 3}

Simplify

= 5

x \to - 3 lim (\frac{x ^{3} + x ^{2} - 21 x - 45}{x ^{3} + 7 x ^{2} + 15 x + 9})

x \to 0.1 lim (x^{x})

x \to 2 lim (\frac{x ^{2} + x}{x + 1})

x \to 2 lim (5 x^{2} - 4 x + 10)

x \to 0 lim ((sin (\frac{1}{x}))^{x})

What is the limit as x approaches 4 of (5x-20)/(x^2-7x+12) ?
The limit as x approaches 4 of (5x-20)/(x^2-7x+12) is 5