y^{''}-2y^'+1y=0,y(0)=5,y^'(0)=4

Lösung

y^{^{''}} - 2 y^{^{'}} + 1 y = 0, y (0) = 5, y^{^{'}} (0) = 4

y = 5 e^{t} - e^{t} t

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 1 y = 0

Solve linear ODE:

y = 5 e^{t} - e^{t} t

y = 5 e^{t} - e^{t} t

d er i v a t i v e ln (x - 9)

\frac{\partial}{\partial x} ((x + 1)^{2} (x^{2} + 2 x))

d er i v a t i v e f (x) = \frac{x ^{3} - 1 x ^{2} + 2}{x ^{2}}

\int (x x + 3) d x

\frac{\partial}{\partial x} (x^{4} + y^{4} + 3 x^{2} y^{3})