derivative C(x)=-0.01x^2+7.2x-163

解答

导数

C (x) = - 0.01 x^{2} + 7.2 x - 163

- 0.02 x + 7.2

求解步骤

\frac{d}{d x} (- 0.01 x^{2} + 7.2 x - 163)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.01 x^{2}) + \frac{d}{d x} (7.2 x) - \frac{d}{d x} (163)

\frac{d}{d x} (0.01 x^{2}) = 0.02 x

\frac{d}{d x} (7.2 x) = 7.2

\frac{d}{d x} (163) = 0

= - 0.02 x + 7.2 - 0

化简

= - 0.02 x + 7.2

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