limit as x approaches infinity of 1/6 ln(tanh((3x)/2))

Lösung

x \to \infty lim (\frac{1}{6} ln (tanh (\frac{3 x}{2})))

0

Schritte zur Lösung

x \to \infty lim (\frac{1}{6} ln (tanh (\frac{3 x}{2})))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{6} \cdot x \to \infty lim (ln (tanh (\frac{3 x}{2})))

Wende die Kettenregel für Grenzen an:

0

= \frac{1}{6} \cdot 0

Vereinfache

= 0

x \to 1 lim (\frac{2 x - 2}{3 26 + x - 3})

x \to \frac{π}{2} + lim (tan (π - x))

x \to 3 lim (2 x - 2)

x \to \infty lim (\frac{2 x}{2 ^{x} ln ( 2 )})

x \to 1 - lim (\frac{x - 2 x ^{- 1}}{4 x ^{- 1}})