integral from 2 to 4 of x^2y+y^2x+x+y

Lösung

\int_{2}^{4} x^{2} y + y^{2} x + x + y d x

2 y + 6 + y^{2} \cdot 6 + \frac{56 y}{3}

Schritte zur Lösung

\int_{2}^{4} x^{2} y + y^{2} x + x + y d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} y d x + \int_{2}^{4} x d x + \int_{2}^{4} y^{2} x d x + \int_{2}^{4} y x^{2} d x

\int_{2}^{4} y d x = 2 y

\int_{2}^{4} x d x = 6

\int_{2}^{4} y^{2} x d x = y^{2} \cdot 6

\int_{2}^{4} y x^{2} d x = \frac{56 y}{3}

= 2 y + 6 + y^{2} \cdot 6 + \frac{56 y}{3}

t a y l or \frac{1}{1 + x ^{- 1}}

y^{^{''}} - 5 y^{^{'}} = 0, y (0) = 6, y^{^{'}} (0) = - 9

\frac{\partial}{\partial x} (ln (x^{4} - y^{4}))

\frac{d}{d x} (I n^{4} x)

d er i v a t i v e \frac{5 x + 1}{5 x - 1}