integral (x^2+2)/(x+2)

Lösung

integral

\frac{x ^{2} + 2}{x + 2}

\frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 6 ln ∣ x + 2 ∣ + C

Schritte zur Lösung

\int \frac{x ^{2} + 2}{x + 2} d x

Wende U-Substitution an

= \int \frac{u ^{2} - 4 u + 6}{u} d u

Multipliziere aus

\frac{u ^{2} - 4 u + 6}{u} : u - 4 + \frac{6}{u}

= \int u - 4 + \frac{6}{u} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u d u - \int 4 d u + \int \frac{6}{u} d u

\int u d u = \frac{u ^{2}}{2}

\int 4 d u = 4 u

\int \frac{6}{u} d u = 6 ln ∣ u ∣

= \frac{u ^{2}}{2} - 4 u + 6 ln ∣ u ∣

Setze in

u = x + 2

ein

= \frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 6 ln ∣ x + 2 ∣

Füge eine Konstante zur Lösung hinzu

= \frac{( x + 2 ) ^{2}}{2} - 4 (x + 2) + 6 ln ∣ x + 2 ∣ + C

in t e g r a l 2 x^{2} + 1

in t e g r a l e^{- 1} f (x)

in t e g r a l \frac{1}{( x + 1 ) ( x ^{2} + 1 ) ^{2}}

in t e g r a l \frac{1}{( 2 + x )}

in t e g r a l cos (t^{3})