y^'+y^5=0

Lösung

y^{^{'}} + y^{5} = 0

y = 4 - \frac{1}{4 ( - t + c _{1} )}, y = - 4 - \frac{1}{4 ( - t + c _{1} )}

Schritte zur Lösung

y^{'} (t) + y^{5} = 0

Solve separable ODE:

y = 4 - \frac{1}{4 ( - t + c _{1} )}, y = - 4 - \frac{1}{4 ( - t + c _{1} )}

y = 4 - \frac{1}{4 ( - t + c _{1} )}, y = - 4 - \frac{1}{4 ( - t + c _{1} )}

x^{2} y^{^{'}} + 2 x y = 0

y^{^{'}} = - 3 x y

y = \frac{1}{2 y ^{^{'}} ( x ) ^{2}}

x^{^{'}} - 2 x = 0

y^{^{'}} - 6 y + 11 y^{^{'}} - 6 y = 0