f^'(x)=(x^2-1)(x+3)

Lösung

f^{^{'}} (x) = (x^{2} - 1) (x + 3)

f (x) = \frac{x ^{4}}{4} + x^{3} - \frac{x ^{2}}{2} - 3 x + c_{1}

Schritte zur Lösung

f^{'} (x) = (x^{2} - 1) (x + 3)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int (x^{2} - 1) (x + 3) d x

\int (x^{2} - 1) (x + 3) d x = \frac{x ^{4}}{4} + x^{3} - \frac{x ^{2}}{2} - 3 x + c_{1}

f (x) = \frac{x ^{4}}{4} + x^{3} - \frac{x ^{2}}{2} - 3 x + c_{1}

f^{^{'}} (x) - 4 = 0

f^{^{'}} (t) = 107

f^{^{'}} (x) = 3 x^{3} + 4 x^{2} - x

f^{^{'}} (x) = 2 x^{3}

f^{^{'}} (x) = 3 x^{3} + 4 x^{2} + 2 x - 9