integral of ((2x+1))/((x^2+9))

Lösung

\int \frac{( 2 x + 1 )}{( x ^{2} + 9 )} d x

ln x^{2} + 9 + \frac{1}{3} arctan (\frac{x}{3}) + C

Schritte zur Lösung

\int \frac{2 x + 1}{x ^{2} + 9} d x

Multipliziere aus

\frac{2 x + 1}{x ^{2} + 9} : \frac{2 x}{x ^{2} + 9} + \frac{1}{x ^{2} + 9}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 x}{x ^{2} + 9} d x + \int \frac{1}{x ^{2} + 9} d x

\int \frac{2 x}{x ^{2} + 9} d x = ln x^{2} + 9

\int \frac{1}{x ^{2} + 9} d x = \frac{1}{3} arctan (\frac{x}{3})

= ln x^{2} + 9 + \frac{1}{3} arctan (\frac{x}{3})

Füge eine Konstante zur Lösung hinzu

= ln x^{2} + 9 + \frac{1}{3} arctan (\frac{x}{3}) + C

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