integral of 1/(2sin(θ))*(-2sin(θ))

解答

\int \frac{1}{2 sin ( θ )} \cdot (- 2 sin (θ)) d θ

- θ + C

求解步骤

\int \frac{1}{2 sin ( θ )} (- 2 sin (θ)) d θ

\frac{1}{2 sin ( θ )} (- 2 sin (θ)) = - 1

= \int - 1 d θ

常数积分:

\int a d x = a x

= (- 1) θ

化简

= - θ

解答补常数

= - θ + C

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