(\partial)/(\partial x)(((a+cx))/(c+b))

Lösung

\frac{\partial}{\partial x} (\frac{( a + c x )}{c + b})

\frac{c}{c + b}

Schritte zur Lösung

\frac{\partial}{\partial x} (\frac{( a + c x )}{c + b})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{c + b} \frac{\partial}{\partial x} (a + c x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{c + b} (\frac{\partial}{\partial x} (a) + \frac{\partial}{\partial x} (c x))

\frac{\partial}{\partial x} (a) = 0

\frac{\partial}{\partial x} (c x) = c

= \frac{1}{c + b} (0 + c)

Vereinfache

\frac{1}{c + b} (0 + c) : \frac{c}{c + b}

= \frac{c}{c + b}

\int cos (θ) sin (θ) d θ

\frac{d y}{d x} = 5 x + y - 5

\frac{\partial}{\partial u} (u sin (v))

\int \frac{1}{( 2 + x ^{2} ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (1 + 4 - x)