integral from 1 to 2 of (2x-1)^4

Lösung

\int_{1}^{2} (2 x - 1)^{4} d x

\frac{121}{5}

Dezimale

24.2

Schritte zur Lösung

\int_{1}^{2} (2 x - 1)^{4} d x

Wende U-Substitution an

= \int_{1}^{3} \frac{u ^{4}}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{3} u^{4} d u

Wende die Potenzregel an

= \frac{1}{2} [\frac{u ^{5}}{5}]_{1}^{3}

Berechne die Grenzen:

\frac{242}{5}

= \frac{1}{2} \cdot \frac{242}{5}

Vereinfache

= \frac{121}{5}

\int_{x}^{x^{4}} \frac{y}{x} d y

\int_{0}^{π} sin^{4} (x) cos (x) d x

\int_{0}^{1} e^{x + x^{2}} d x

\int_{- 1}^{0} (x - x^{2}) d x

\int_{1}^{2} x^{3} + 3 x d x