integral from 1 to 2 of 4/6+4z

Lösung

\int_{1}^{2} \frac{4}{6} + 4 z d z

\frac{20}{3}

Dezimale

6.66666 \dots

Schritte zur Lösung

\int_{1}^{2} \frac{4}{6} + 4 z d z

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{4}{6} d z + \int_{1}^{2} 4 z d z

\int_{1}^{2} \frac{4}{6} d z = \frac{2}{3}

\int_{1}^{2} 4 z d z = 6

= \frac{2}{3} + 6

Vereinfache

\frac{2}{3} + 6 : \frac{20}{3}

= \frac{20}{3}

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