integral from 1 to e of ((ln(u)+1)/u)

Lösung

\int_{1}^{e} (\frac{ln ( u ) + 1}{u}) d u

\frac{3}{2}

Dezimale

1.5

Schritte zur Lösung

\int_{1}^{e} \frac{ln ( u ) + 1}{u} d u

Wende U-Substitution an

= \int_{1}^{2} v d v

Wende die Potenzregel an

= [\frac{v ^{2}}{2}]_{1}^{2}

Berechne die Grenzen:

\frac{3}{2}

= \frac{3}{2}

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