integral from 0 to sqrt(x^2+y^2 of)1

Lösung

\int_{0}^{x^{2} + y^{2}} 1 d z

x^{2} + y^{2}

Schritte zur Lösung

\int_{0}^{x^{2} + y^{2}} 1 d z

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot z]_{0}^{x^{2} + y^{2}}

Vereinfache

= [z]_{0}^{x^{2} + y^{2}}

Berechne die Grenzen:

x^{2} + y^{2}

= x^{2} + y^{2}

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