integral from 1 to 2 of (x-3y^2)

Lösung

\int_{1}^{2} (x - 3 y^{2}) d y

x - 7

Schritte zur Lösung

\int_{1}^{2} x - 3 y^{2} d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d y - \int_{1}^{2} 3 y^{2} d y

\int_{1}^{2} x d y = x

\int_{1}^{2} 3 y^{2} d y = 7

= x - 7

\int_{0}^{\frac{1}{2}} 2 x^{2} + x d x

\int_{- 2}^{2} (4 - x^{2})^{3} d x

\int_{0}^{1} 1 - x^{2} x^{2} d x

\int_{1}^{2} (1 - 3 x + 2 x^{2}) d x

\int_{- 1}^{2} (3 x - x^{2}) d x