integral from 0 to 1 of e^x+2x

Lösung

\int_{0}^{1} e^{x} + 2 x d x

e

Dezimale

2.71828 \dots

Schritte zur Lösung

\int_{0}^{1} e^{x} + 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e^{x} d x + \int_{0}^{1} 2 x d x

\int_{0}^{1} e^{x} d x = e - 1

\int_{0}^{1} 2 x d x = 1

= e - 1 + 1

Vereinfache

= e

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