integral from 0 to 1 of 1/2 (x^2-x^4)

Lösung

\int_{0}^{1} \frac{1}{2} (x^{2} - x^{4}) d x

\frac{1}{15}

Dezimale

0.06666 \dots

Schritte zur Lösung

\int_{0}^{1} \frac{1}{2} (x^{2} - x^{4}) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{1} x^{2} - x^{4} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{1} x^{2} d x - \int_{0}^{1} x^{4} d x)

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} x^{4} d x = \frac{1}{5}

= \frac{1}{2} (\frac{1}{3} - \frac{1}{5})

Vereinfache

\frac{1}{2} (\frac{1}{3} - \frac{1}{5}) : \frac{1}{15}

= \frac{1}{15}

\int_{- \infty}^{\infty} 2 d x

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