integral from-2 to 2 of 16^{x/2}

Lösung

\int_{- 2}^{2} 1 6^{\frac{x}{2}} d x

\frac{255}{32 ln ( 2 )}

Dezimale

11.49647 \dots

Schritte zur Lösung

\int_{- 2}^{2} 1 6^{\frac{x}{2}} d x

Vereinfache

1 6^{\frac{x}{2}} : 4^{x}

= \int_{- 2}^{2} 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{4 ^{x}}{ln ( 4 )}]_{- 2}^{2}

\frac{4 ^{x}}{ln ( 4 )} = \frac{2 ^{2 x - 1}}{ln ( 2 )}

= [\frac{2 ^{2 x - 1}}{ln ( 2 )}]_{- 2}^{2}

Berechne die Grenzen:

\frac{255}{32 ln ( 2 )}

= \frac{255}{32 ln ( 2 )}

\int_{0}^{4} x 4 x - x^{2} d x

\int_{- π}^{0} \frac{1}{π}

\int_{- 2}^{2} 5 t^{4} d t

\int_{0}^{1} (1 - x^{2}) cos (nπ x) d x

\int_{0}^{2} 1 + (2 - 2 x)^{2} d x