integral from 6 to 10 of 1x^{-2}

Lösung

\int_{6}^{10} 1 x^{- 2} d x

\frac{1}{15}

Dezimale

0.06666 \dots

Schritte zur Lösung

\int_{6}^{10} 1 \cdot x^{- 2} d x

Vereinfache

1 \cdot x^{- 2} : \frac{1}{x ^{2}}

= \int_{6}^{10} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{6}^{10}

Berechne die Grenzen:

\frac{1}{15}

= \frac{1}{15}

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