integral from 0 to a of sqrt(1-x^2)

Lösung

\int_{0}^{a} 1 - x^{2} d x

\frac{1}{2} (arcsin (a) + \frac{1}{2} sin (2 arcsin (a)))

Schritte zur Lösung

\int_{0}^{a} 1 - x^{2} d x

Trigonometrische Substitution anwenden

= \int_{0}^{a r c s i n (a)} cos^{2} (u) d u

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= \int_{0}^{a r c s i n (a)} \frac{1 + cos ( 2 u )}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{a r c s i n (a)} 1 + cos (2 u) d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{a r c s i n (a)} 1 d u + \int_{0}^{a r c s i n (a)} cos (2 u) d u)

\int_{0}^{a r c s i n (a)} 1 d u = arcsin (a)

\int_{0}^{a r c s i n (a)} cos (2 u) d u = \frac{1}{2} sin (2 arcsin (a))

= \frac{1}{2} (arcsin (a) + \frac{1}{2} sin (2 arcsin (a)))

\int_{- \infty}^{1} 3 e^{\frac{x}{2}} d x

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