sum from n=0 to infinity of 6/(7^n)

Lösung

n = 0 \sum \infty \frac{6}{7 ^{n}}

7

Schritte zur Lösung

n = 0 \sum \infty \frac{6}{7 ^{n}}

Wende die Regel der konstanten Multiplikation:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 6 \cdot n = 0 \sum \infty \frac{1}{7 ^{n}}

Geometrischen Test der Reihe anwenden:

\frac{7}{6}

= 6 \cdot \frac{7}{6}

Vereinfache

6 \cdot \frac{7}{6} : 7

= 7

x = 1 \sum \infty \frac{2 ^{x}}{5 ^{x}}

n = 0 \sum \infty cos (6 n)

n = 0 \sum \infty (\frac{1}{23})^{n}

n = 1 \sum \infty (\frac{n}{e})^{n}

n = 1 \sum \infty 3 (\frac{2}{5})^{n}