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Beliebt Rechnen >

sum from n=2 to infinity of 1/(n*(n-1))

Lösung

n = 2 \sum \infty \frac{1}{n \cdot ( n - 1 )}

Lösung

1

Schritte zur Lösung

n = 2 \sum \infty \frac{1}{n ( n - 1 )}

Teleskopreihen-Test anwenden:

1

= 1

Beliebte Beispiele

sum from n=0 to infinity of (2n^2)/(n!)

n = 0 \sum \infty \frac{2 n ^{2}}{n !}

sum from k=1 to infinity of ke^{-2k^2}

k = 1 \sum \infty k e^{- 2 k^{2}}

sum from n=1 to infinity of (7/9)^{n-1}

n = 1 \sum \infty (\frac{7}{9})^{n - 1}

sum from n=3 to infinity of (4^n)/(3^n)

n = 3 \sum \infty \frac{4 ^{n}}{3 ^{n}}

sum from n=1 to infinity of sec(n)

n = 1 \sum \infty sec (n)