2xy+6x+(x^2-9)y^'=0

Lösung

2 x y + 6 x + (x^{2} - 9) y^{^{'}} = 0

y = \frac{c _{1}}{x ^{2} - 9} - 3

Schritte zur Lösung

2 x y + 6 x + (x^{2} - 9) y^{'} (x) = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9} - 3

y = \frac{c _{1}}{x ^{2} - 9} - 3

\frac{d y}{d x} - \frac{x}{2 y} = 0

e^{x} y \frac{d y}{d x} = e^{- y} (1 + e^{- 2 x})

x d y + y d x = 2 d x

\frac{d y}{d x} = - (x y)^{2}

y^{^{'}} - x^{2} y = 0