(x^2+e^x)dx+ydy=0

Lösung

(x^{2} + e^{x}) d x + y d y = 0

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

Schritte zur Lösung

(x^{2} + e^{x}) d x + y d y = 0

Solve separable ODE:

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

y = \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}, y = - \frac{- 2 x ^{3} - 6 e ^{x} + c _{1}}{3}

x^{^{'}} = \frac{x ^{2} - 1}{2}

\frac{d y}{d x} = 3 x 2 y

\frac{d h}{d t} = - \frac{3}{100} h - 16

\frac{d y}{d x} + x^{3} y = 2 x^{3}

3 x y^{^{'}} - 5 y = 0