(dy)/(dx)+(x^2-4)y=x^2-4

Lösung

\frac{d y}{d x} + (x^{2} - 4) y = x^{2} - 4

y = e^{- \frac{x ^{3}}{3} + 4 x + c_{1}} + 1

Schritte zur Lösung

\frac{d y}{d x} + (x^{2} - 4) y = x^{2} - 4

Solve separable ODE:

y = e^{- \frac{x ^{3}}{3} + 4 x + c_{1}} + 1

y = e^{- \frac{x ^{3}}{3} + 4 x + c_{1}} + 1

\frac{d y}{d x} = \frac{1 - y ^{2}}{1 - x ^{2}}

y^{^{'}} + 2 y = - 1

\frac{d x}{d t} = 45 - \frac{x}{100}

\frac{d y}{d x} = 3 x + 5 x y^{2}

7 y y^{^{'}} = 5 x