yln(x) d/(dy)(x)=((y+1)/x)^2,y=5,x=4

解答

y ln (x) \frac{d}{d y} (x) = (\frac{y + 1}{x})^{2}, y = 5, x = 4

\frac{9}{4}

十进制

2.25

求解步骤

给定

y = 5, x = 4

找到

(\frac{y + 1}{x})^{2}

\frac{y + 1}{x} : \frac{5 + 1}{4}

= (\frac{5 + 1}{4})^{2}

乘开

(\frac{5 + 1}{4})^{2} : \frac{9}{4}

= \frac{9}{4}

y^{^{'}} = \frac{1}{2} x 1 - 16 y^{2}, y (0) = 0

y^{^{'}} = 4 y^{- 2} (x^{6} + x^{4} + x^{2}), y (0) = 0

\frac{d y}{d x} = - x^{5} y^{2}

\frac{d P}{d t} = 7 Pt, P (1) = 2

(1 + y^{2}) d x = (x + x^{2}) d y