(dv)/(dt)=v^2+16

Lösung

\frac{d v}{d t} = v^{2} + 16

v = 4 tan (4 t + c_{1})

Schritte zur Lösung

\frac{d v}{d t} = v^{2} + 16

Solve separable ODE:

v = 4 tan (4 t + c_{1})

v = 4 tan (4 t + c_{1})

y^{^{'}} = x y^{2} - x

\frac{d y}{d x} = - 6 y

(tan (x) \frac{d y}{d x}) - y = a

\frac{d p}{d t} = t^{2} p - 2 p + t^{2} - 2

x y^{^{'}} - 1 = y^{2}