(x-1)y^'=(4-y^2)

解答

(x - 1) y^{^{'}} = (4 - y^{2})

y = - \frac{2 e ^{4 c_{1}} x ^{4}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x ^{3}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{12 e ^{4 c_{1}} x ^{2}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2 e ^{4 c_{1}}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x}

求解步骤

(x - 1) y^{'} (x) = (4 - y^{2})

求解可分离方程:

y = - \frac{2 e ^{4 c_{1}} x ^{4}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x ^{3}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{12 e ^{4 c_{1}} x ^{2}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2 e ^{4 c_{1}}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x}

y = - \frac{2 e ^{4 c_{1}} x ^{4}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x ^{3}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{12 e ^{4 c_{1}} x ^{2}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} + \frac{8 e ^{4 c_{1}} x}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2 e ^{4 c_{1}}}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x} - \frac{2}{1 - e ^{4 c_{1}} x ^{4} - e ^{4 c_{1}} + 4 e ^{4 c_{1}} x ^{3} - 6 e ^{4 c_{1}} x ^{2} + 4 e ^{4 c_{1}} x}

\frac{d y}{d x} = sin (x) tan (y)

\frac{d y}{d x} + 5 y = 50

(t^{2} + 1) y^{^{'}} + t y = 0

\frac{d y}{d x} = 3 y - 2

5 y + 5 + (5 x - 7) \frac{d y}{d x} = 0