y^'-2xy=-4x

Lösung

y^{^{'}} - 2 x y = - 4 x

y = e^{x^{2} + c_{1}} + 2

Schritte zur Lösung

y^{'} (x) - 2 x y = - 4 x

Solve separable ODE:

y = e^{x^{2} + c_{1}} + 2

y = e^{x^{2} + c_{1}} + 2

y - x y^{^{'}} = 0

y^{^{'}} + 2 x y = 3 x

\frac{d y}{d x} = x^{4} (y - 3), y (0) = 9

\frac{d y}{d x} + \frac{2 x y}{x ^{2} - 1} = \frac{x}{x ^{2} - 1}

\frac{d y}{d x} = - \frac{8}{4} x^{3} y^{5}