y^'*x=2y

Lösung

y^{^{'}} \cdot x = 2 y

y = c_{1} x^{2}

Schritte zur Lösung

y^{'} (x) \cdot x = 2 y

Solve separable ODE:

y = c_{1} x^{2}

y = c_{1} x^{2}

y^{^{'}} = 5 y^{- 4}, y (2) = 5

- y^{^{'}} + y = 10

\frac{d y}{d x} = - \frac{3}{9} x^{5} y^{8}

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (15)

\frac{d y}{d x} = - \frac{y}{a}