y^'+y/(10)= v/(10)

Lösung

y^{^{'}} + \frac{y}{10} = \frac{v}{10}

y = - e^{\frac{- t - c _{1}}{10}} + v

Schritte zur Lösung

y^{'} (t) + \frac{y}{10} = \frac{v}{10}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{10}} + v

y = - e^{\frac{- t - c _{1}}{10}} + v

\frac{d y}{d t} - 6 t y^{2} = 0

y + 5 + (x - 2) y^{^{'}} = 0

y^{^{'}} - x y^{2} = x

y^{^{'}} = - 5 y + 20

y^{^{'}} = 8 t cos^{2} (y), y (1) = \frac{3 π}{4}