x= y/(y^'+y)

Lösung

x = \frac{y}{y ^{^{'}} + y}

y = e^{- x + c_{1}} x

Schritte zur Lösung

x = \frac{y}{y ^{'} ( x ) + y}

Solve separable ODE:

y = e^{- x + c_{1}} x

y = e^{- x + c_{1}} x

20 (\frac{d v}{d t}) = - (20) (32) - 0.0025 v

\frac{d y}{d x} \cdot (1 + e^{x}) = e^{x - y}

y^{^{'}} = y tan (x)

\frac{d x}{d t} = t e^{x}, x = 1

\frac{d y}{d x} = 2 x^{3} y^{4}