y^'+6e^{x+y}=0

Lösung

y^{^{'}} + 6 e^{x + y} = 0

y = - ln (6 e^{x} - c_{1})

Schritte zur Lösung

y^{'} (x) + 6 e^{x + y} = 0

Solve separable ODE:

y = - ln (6 e^{x} - c_{1})

y = - ln (6 e^{x} - c_{1})

(1 - cos (x)) d y + (2 y sin (x) tan (x)) d x = 0

\frac{d y}{d t} - y = 0, y (0) = 10

\frac{d y}{d x} x^{2} + y^{2} = 0

\frac{d x}{d t} = a x - b x^{2}

y^{^{'}} + a x y = 0