derivative of 2yln(y)=(dx)/(dx)

Lösung

\frac{d}{d x} (2 y ln (y)) = \frac{d x}{d x}

2 (ln (y) \frac{d y}{d x} + \frac{d y}{d x}) = 1

Schritte zur Lösung

\frac{d}{d x} (2 y ln (y)) = \frac{d x}{d x}

\frac{d}{d x} (2 y ln (y)) = 2 (ln (y) \frac{d y}{d x} + \frac{d y}{d x})

2 (ln (y) \frac{d y}{d x} + \frac{d y}{d x}) = \frac{d x}{d x}

\frac{d x}{d x} = 1

2 (ln (y) \frac{d y}{d x} + \frac{d y}{d x}) = 1

\frac{d y}{d x} = x^{2} y^{5}

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

y^{^{'}} = t y^{\frac{1}{2}}, y (0) = 0

\frac{d y}{y} = x^{13} d x

\frac{d y}{d x} y = 9 x + 7