(x^2-3)y^{-1}+2xy^'=0

Lösung

(x^{2} - 3) y^{- 1} + 2 x y^{^{'}} = 0

y = \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}, y = - \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}

Schritte zur Lösung

(x^{2} - 3) y^{- 1} + 2 x y^{'} (x) = 0

Solve separable ODE:

y = \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}, y = - \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}

y = \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}, y = - \frac{- x ^{2} + 6 ln ( x ) + c _{1}}{2}

y^{^{'}} = y (1 - x), y (1) = e

4 y = y^{^{'}}

x y d x + d y = 0

(sin (x)) d y = 2 y (cos (x)) d x

- (x y^{^{'}} + y) (csc (2) (x y) - 1) = 0