xy^'-2y+4=0

Lösung

x y^{^{'}} - 2 y + 4 = 0

y = c_{1} x^{2} + 2

Schritte zur Lösung

x y^{'} (x) - 2 y + 4 = 0

Solve separable ODE:

y = c_{1} x^{2} + 2

y = c_{1} x^{2} + 2

y^{^{'}} = \frac{( x ^{3} + x )}{4 y ^{3}}

y^{^{'}} = 0.002 \cdot (1000 - y), y (0) = 1

v = 50 x \frac{d v}{d x}

\frac{d x}{d t} = 18 - 0.72 \cdot x

y^{^{'}} = - \frac{y}{2} + 4