(dy)/(dt)=t^2(1+y^2)

Lösung

\frac{d y}{d t} = t^{2} (1 + y^{2})

y = tan (\frac{t ^{3}}{3} + c_{1})

Schritte zur Lösung

\frac{d y}{d t} = t^{2} (1 + y^{2})

Solve separable ODE:

y = tan (\frac{t ^{3}}{3} + c_{1})

y = tan (\frac{t ^{3}}{3} + c_{1})

\frac{d y}{d x} = \frac{( 2 - x )}{( y - 1 )}

e^{x + 2 y} - e^{- 3 y} y^{^{'}} = 0

4 y^{^{'}} = 1 + x + y + x y

y^{^{'}} + 18 y^{^{'}} + 81 y = 0

\frac{d y}{d x} = (- n y)